Tentukan pada gambar : a. Percepatan system b. Tegangan tali

a. Tinjau balok A
∑Fx = mA.a
T = mA.a
T = 30a

b. Tinjau balok B
∑Fy = mB.a
mB.g - T = mB.a
10.10 - T = 10a
100 - T = 10a

c. Substitusi nilai T
100 - 30a = 10a
100 = 40a
a = 100/40
a = 2,5 m/s^2

T = 30.a
T = 30.2,5
T = 75

m A = 30 kg
m B = 10 kg

Berat balok A (w A):
w A = m A.g
w A = 30.10 ⇐ g = 10 m/s²
w A = 300 N

Berat balok B (w B):
w B = m B.g
w B = 10.10 ⇐ g = 10 m/s²
w B = 100 N

a.) Percepatan sistem (a):
a = w B/m A + m B
a = 100/30 + 10
a = 100/40
a = 2,5 m/s² ⇐ Hasil

b.) Tegangan tali (T):
T = m B.a + w B
T = 10.2,5 + 100
T = 25 + 100
T = 125 N ⇐ Hasil