persamaan garis lurus yang melalui titik (-3,5) dan bergradien -1/2

y-y1 = m(x-x1)
y-5 = -1/2 (x-(-3))
y-5 = -1/2 (x + 3)
y-5 = -1/2x -3/2
y = -1/2x + 7/2

y-y1=m(x-x1)
Y-5 =-1/2 (X+3)
2Y-10 = -1X - 3
2Y+1X-7=0
...
..

Maaf klo salah