jika x ≠1 dan x>0 nilai x yang memenuhi persamaan ^xlog (x+2) - 3^xlog 2+1 =0

^xlog (x + 2) - ^xlog 2³ = -1
^xlog (x + 2)/8 = ^xlog (1/x)
(x + 2) / 8 = 1 / x
x(x + 2) = 8
x² - 2x - 8 = 0
(x + 2)(x - 4) = 0
x = -2 atau x = 4
karena x > 0
maka nilai x = 4