persamaan garis yang melalui titik(-6,1)dan sejajar dengan gari persamaan y= 5/3 x +10

m=5/3
y-1=5/3(x+6)
y-1=5/3x+10
y=5/3x+11

m = x/y
m = 5/3/1
m = 5/3

y-y1 = m(x-x1)
y-1 = 5/3(x-(-6))
3(y-1) = 5 ( x+6)
3y-3 = 5x + 30
3y = 5x + 30 - 3
3y = 5x + 27