tentukan nilai simpangan baku dari data 7,4,4,1,5,6,8,5 tolong bantu ya kak

langsung aja y

X = (7+4+4+1+5+6+8+5) / 8
X = 40 / 8 = 5

maka

Sb = √(7-5)²+2(4-5)²+(1-5)²+2(5-5)²+(6-5)²+(8-5)² / 8

Sb = √4+2+16+0+1+9 / 8

Sb = √ 32/8

Sb = √4 = 2

jadi simpangan bakunya yaitu 2

semoga berguna +_+

Rata2= 7+4+4+1+5+6+8+5
= 40:8=5
√(7-5)^2+(4-5)^2+(4-5)^2+(1-5)^2+(5-5)^2+(6-5)^2+(8-5)^2+(5-5)^2/8
=√4+1+1+16+0+1+9+0/8
= √32/8
=√4
=2