Persamaan garis melalui titik (1,-3) dan sejajat dengan garis 2x-3y= -1 adalah

langsung aja y

2x - 3y = -1
3y = 2x + 1 (÷3)
y = ⅔x + ⅓ → m = ⅔

maka
y - y1 = m (x-x1)
y + 3 = ⅔ (x -1)
y + 3 = ⅔x - ⅔ (×3)
3y + 9 = 2x - 2
2x - 3y -9 - 2 = 0
2x - 3y - 11 = 0

semoga berguna +_+

(1,-3)
2x-3y = -1
m = -a/b = -2/-3 = 2/3

syarat sejajar m₁=m₂

persamaan garis lurus
y-y₁ = m(x-x₁)
y-(-3) = 2/3(x-1)
y+3 = 2/3(x-1)
3(y+3) = 3[2/3(x-1)]
3y+9 = 2(x-1)
3y+9 = 2x-2
-2x+3y = -2-9
-2x+3y = -11
-2x+3y+11 = 0
2x-3y-11 = 0