Titik stasioner dari fungsi f(x)=1/3x^3-2x^2-5 adalah . . .

f(x) = 1/3 x^3 - 2x^2 - 5

Titik stasioner, f'(x) = 0

3 × 1/3 x^(3 - 1) - 2 × 2x^(2 - 1) - 0 = 0
x^2 - 4x = 0
x(x - 4) = 0

1) x = 0 --> y = f(0) = 1/3 (0)^3 - 2(0)^2 - 5
= 0 - 0 - 5
= -5

2) x = 4 --> y = f(4) = 1/3 (4)^3 - 2(4)^2 - 5
= 1/3 × 64 - 2 × 16 - 5
= 64/3 - 32 - 5
= 64/3 - 37
= 64/3 - 111/3
= -47/3