Matematika

Pertanyaan

Tolong yg no.3 itu gimana caranya?
Tolong yg no.3 itu gimana caranya?

0 Comment.

1 Jawaban

  • AC/(sin B) = BC/(sin A)
    20/(sin B) = (20√2)/(sin 45°)
    20/(sin B) = (20√2)/(1/2 √2)
    20/(sin B) = 40
    Sin B = 20/40 = 1/2 = sin 30° => <B = 30°
    <A + <B + <C = 180°
    45° + 30° + <C = 180°
    <C = 180° - 75° = 105°

Pertanyaan Lainnya