∫sin 4x cos^-3/4 4x dx Ket: ^ = pangkat

Misal : u = cos 4x
=> du/dx = - 4 sin 4x => dx = du/(-4 sin 4x)
Int (sin 4x . cos^-3/4 4x dx
= Int (sin 4x . u^-3/4 du/(-4 sin 4x)
= Int (-1/4 u^-3/4) du
= (-1/4)/(1/4) u^(1/4) + C
= -1 u^(1/4) + C
= - cos^1/4 4x + C