2√75+4√48-3√12 bantuin sihh

2akar75+4akar48-3akar12 = 2.5akar3+4.4akar3-3.2akar3 = 10akar3+16akar3-6akar3 = 20akar3

2√75 + 4√48 - 3√12
2(√25*√3) + 4(√16*√3) - 3(√4*√3)
2(5*√3) + 4(4*√3) - 3(2*√3)
10√3 + 16√3 - 6√3
20√3