Harap bantuannya tentang integral soal ada digambar

Int (3x^3 + 2x^2 - 3x)/2x dx
= Int (3x^3/2x + 2x^2/2x - 3x/2x) dx
= Int (3/2)x^2+ x - 3/2 dx
= (3/2).1/3 x^3 + 1/2 x^2 - (3/2)x | batas 1 sampai 3
= 1/2 x^3 + 1/2 x^2 - 3/2 x | batas 1 sampai 3
= (1/2 . 3^3 + 1/2 . 3^2 - 3/2 . 3) - (1/2 . 1^3 + 1/2 . 1^2 - 3/2 . 1)
= (27/2 + 9/2 - 9/2) - (1/2 + 1/2 - 3/2)
= (27/2) - (-1/2)
= 28/2
= 14