Diketahui f(x) = (1/2π)^× , maka rumus f^-1(x) =

fungsi invers
f(x)= (π/2)ˣ
f⁻¹ { (π/2)ˣ} = x
y = (π/2 )ˣ
log y = x . log (π/2)
x = (π/2)'log y = (π/2)'log y
f⁻¹ (y) = (π/2)'log y
f⁻¹ (x) = (π/2)'log x