Diketahui fungsi f : R➡R, yang ditentukan dengan F(x-4) = 2x+9/x+1. Rumus untuk f^-1(x) =

fungsi invers

f(x-4) = (2x +9)/(x+1)
f⁻¹ (x)= ..

f⁻¹ { (2x+9)/(x+1)} = x - 4
(2x +9)./(x+1)= a
a(x+1)= 2x +9
ax + a = 2x +9
ax- 2x = 9 - a
x(a - 2)= (9-a)
x = (9-a)/(a-2)

f⁻¹(a) = (9-a)/(a-2)  - 4 = {(9-a) -4(a-2)}/(a-2)
f⁻¹(a) = (9-a-4a+8)/ (a-2)
f⁻¹(a)= (17 - 5a)/(a-2)
f⁻¹(x) = (17-5x) /(x - 2)