hitunglah ph campuran 100 ml ch3cooh 0,1 m dgn 100 ml naoh 0,1 m kach3cooh= 10-5

mol CH3COOH => 100 × 0,1 = 10mmol
mol NaOH => 100 × 0,1 = 10 mmol

CH3COOH + NaOH --> CH3COONa + H20
m : 10mmol 10mmol -
r : 10mmol 10mmol 10mmol
s : - - 10mmol

[CH3COONa] = 10mmol/200mL = 0,05 M

[OH-] = √kw/ka × [g]
= √10^-14/10^-5 × [5×10^-2]
= √10^-9 × [5×10^-2]
= √5 × 10^-11
= 2,2 × 10^-5,5 M

pOH = - log 2,2 × 10^-5,5
= 5,5 - log 2,2

pH = 14 - (5,5 - log 2,2)
= 8,5 + log 2,2 sampai sini boleh tapi kalo mau cari nilai log 2,2nya juga boleh

Jadi = 8,5 + 0,34 = 8,84