Nilai dari 2log 18 – 2log 8 + 2log 1/96– 2log 48 ?? tolong bantu jawab dongg.... Masih bingung ini ~~~

2log18 - 2log8 + 2log1/96 - 2log48
= 2log18 + 2log1/96 - 2log8 - 2log48
= 2log18 + 2log1/96 - 2log48 - 2log8
= 2log (18 x 1/96 : 48) - 2log2^3
= 2log (18/4608) - 3 . 2log2
= 2log (1/256) - 3 . 1
= 2log2^(-8) - 3
= -8 - 3
= -11