koordinat titik balik maksimum grafik y = - 2x*-4x+5
Matematika
devyusra
Pertanyaan
koordinat titik balik maksimum grafik y = - 2x*-4x+5
2 Jawaban
-
1. Jawaban whongaliem
y = - 2x² - 4x + 5 ⇒ a = - 2 ; b = - 4 ; c = 5
TB maks ( - b/2a , D/-4a)
x maks = - b/ 2a
= - (- 4/-2.2)
= - (4/4)
= - 1
y.maks = D / -4a
= (b² - 4ac) / - (4 . -2)
= {(-4)² - 4.(-2)(5) / 8
= (16 + 40) / 8
= 56/8
= 7
jadi, ftitik balik maksimum (- 1 , 7) -
2. Jawaban arsetpopeye
y = -2x^2 - 4x + 5
Sumbu simetri x = -b/2a = -(-4)/(2(-2) = -1
y = -2(-1)^2 - 4(-1) + 5 = -2 + 4 + 5 = 7
Jadi koordinat titik balik = (-1,7)