3 log p + 9× p log 3 =6
Matematika
igel4
Pertanyaan
3 log p + 9× p log 3 =6
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1. Jawaban arsetpopeye
3logp + 9 . plog3 = 6
3logp + 9 . 1/(3logp) = 6
Misal 3logp = a
a + 9/a = 6 ........ (kali a)
a^2 + 9 = 6a
a^2 - 6a + 9 = 0
(a - 3)(a - 3) = 0
a = 3
3logp = 3
3logp = 3log3^3
p = 3^3 = 27