Matematika

Pertanyaan

Berapakah nilai 3log120,jika 2log3=p, 3log 5=q

1 Jawaban

  • = ³log120
    = ³log2 + ³log2 + ³log2 + ³log3 + ³log5
    = 1/p + 1/p + 1/p + 1 + q
    = 1 + 3/p + q
    = (pq+p+3)/p

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