Berapakah nilai 3log120,jika 2log3=p, 3log 5=q
Matematika
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Pertanyaan
Berapakah nilai 3log120,jika 2log3=p, 3log 5=q
1 Jawaban
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1. Jawaban ghonii2912
= ³log120
= ³log2 + ³log2 + ³log2 + ³log3 + ³log5
= 1/p + 1/p + 1/p + 1 + q
= 1 + 3/p + q
= (pq+p+3)/p