tolong dibantu yah . ABCD trapesium sama kaki dan sebangun dengan EFGH. jika panjang EF = 24cm, HG = 14 cm, EH = 13cm dan DC = 21cm, maka luas daerah yang diars

luas trapesium = (a + b)/2 × t

♦ t trapesium kecil
HG + 2x = EF
14 + 2x = 24
2x = 10
x = 5 cm

t² = EH² - x²
t² = 13² - 5²
t² = 169 - 25
t² = 144
t = 12 cm

♦ luas trapesium kecil
= (HG + EF)/2 × 12
= (14 + 24)/2 × 12
= 38/2 × 12
= 19 × 12
= 228 cm²

♦ t trapesium besar
HG/DC = EF/AB
14/21 = 24/AB
AB = 24 × 21/14
AB = 36 cm

EH/AD = HG/DC
13/AD = 14/21
AD = 13 × 21/14
AD = 19,5 cm

EF + 2x = AB
24 + 2x = 36
2x = 12
x = 6 cm

t² = AD² - x²
t² = 19,5² - 6²
t² = 380,25 - 36
t² = 344,25
t = 9/2 √17
t = 18,554 cm

♦ luas trapesium besar
= (DC + AB)/2 × t
= (21 + 36)/2 × 9/2 √17
= 57/2 × 9/2 √17
= 513/4 √17
= 128,25 √17 cm²
= 528,788 cm²

♦ luas arsir
528,788 - 228
= 300,788 cm²

maaf bila salah