Tuliskan persamaan garis melalui titik (-6,4) dengan m4

m = 4
y-4 = 4(x+6)
y - 4 = 4x + 24
4x - y + 24 + 4 = 0
4x - y + 28 = 0

m = 2
y - 4 = 2(x + 6)
y - 4 = 2x + 12
2x - y + 12 + 4 = 0
2x - y + 16 = 0

titik (-6,4)
m = 4
persamaan garis lurusnya
y-y₁ = m(x-x₁)
y-4 = 4(x-(-6))
y-4 = 4(x+6)
y-4 = 4x+24
-4x+y = 24+4
-4x+y = 28
-4x+y-28 = 0
4x-y+28 = 0