bisa di bantu kan ka..

f(x) = 3x-2[tex]f(x) = \frac{3x-2}{ 5x+8} y = \frac{3x-2}{ 5x+8} \\ 5xy+8y=3x-2 \\ x(5y-3)=-2-8y \\ x= \frac{-2-8y}{-3+5y} \\[tex]f(x) = \frac{2x+3}{4-5x} \\ y= \frac{2x+3}{4-5x} \\ 4y-5xy = 2x-+3 \\ -5xy-2x=3-4y \\ x(-5y-2)=3-4y \\ f ^{-1} (x) = \frac{-4x+3}{-5x-2} \\ f ^{x-2} (x) = \frac{-4(x-2)+3}{-5(x-2)-2} = \frac{-4x+8+3}{-5x+10-2} = \frac{-4x+11}{-5x+8} \\ = - ( \frac{-4x+11}{-5x+8}) \\ = \frac{4x-11}{5x-8} \\ (D)[/tex] \\ -(\frac{-8x-2}{5x-3}) \\ = \frac{8x+2}{-5x+3} (D)[/tex]
yang nomer selanjutnya hasilnya E tapi aku capek nulis disini hemm caranya diotak atik sendiri ya ^^