tolong nomer 10 pakek cara ya.. makasih

g(x) = x⁴+ 2x³-ax²-14x+b
x²+3x-4 => (x+4)(x-1), x=-4 V x=1

g(-4) => (-4)⁴ + 2(-4)³ - a(-4)² - 14(-4) + b = 0
=> 256 - 128 -16a + 56 + b = 0
=> -16a + b = -184 (i)

g(1) => (1)⁴ + 2(1)³ - a(1)² - 14(1) + b = 0
=> 1 + 2 - a - 14 + b = 0
=> -a + b = 11 (ii)

eliminasi (i) dan (ii)
-16a+b=-184
-a+b=11
_______________-
-15a = -195
a = 39

subs nilai a ke (ii)
-(39) + b = 11
b = 50

masukkan nilai a dan b ke g(x)
g(x)= x⁴+2x³-39x²-14x+50

soalnya jika g(x) dibagi x+1 maka bersisa...
x+1 = 0
x = -1

*skema horner

| 1 2. -39. -14. 50
x=-1 | -1. -1. 40. -26
___________________________ +
1 1. -40. 26. 24

jadi sisanya ialah 24 (E)