Tolong bantu pakai cara nya 2 dan 3

2][
c = 0,55 kal/g°C
m = 50 g
ΔT = -5°-(-45)° = 40°C
Q = ?
Penyelesaian:
Q = m c ΔT
Q = (50)(0,55)(40)
Q = 1100 kal = 1,1 kkal (a)

3][
Q terima = Q lepas
(m c ΔT) = (m c ΔT)
300 (40 -0)= m (100 -40)
12.000 = 60m
m = 12.000/60
m = 200 g (e)